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  1. Mencoba menjawab ya prof., mohon koreksinya.
    Diagonal =√(2)
    diagonal =1+x
    Maka x=√(2) -1
    diameter=√(2) – 2x =√(2) – 2√(2)+2=2-√(2)
    luas lingkaran putih=¹/₄ π(2-√(2))²=¹/₄ π(6-4√(2))=π(³/₂ -√(2))
    luas 2 tembereng=2(¹/₄π(1²)-¹/₂(1)(1) )=π/₂ – 1
    Area biru=π/₂ – 1 -(π(³/₂-√(2)))
    = (√2-1)π – 1
    ≈0,3012902846

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